32. The debate team plans to make and sell trail

Mathematics

1 answer:

Paraphin [41]2 years ago

8 0

Answer:

Step-by-step explanation:

The first equation has to be the ratio of raisins to sunflower seeds. If r is raisins and p is sunflower seeds and there are 3 times as many raisins as sunflower seeds then the first equation must be 3r=p

The second equation should model the prices properly. Raisins are 1.5 per pound and sunflower seeds are 4 per pound, because of this we should have 1.5r (r being each pound of raisins) and 4p (p being each pound of sunflower seeds). From this we know the second equation must be 4p+1.5r=34

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In a certain Algebra 2 class of 27 students, 18 of them play basketball and 16

Bogdan [553]

Answer:

<em>The probability is 0.89 or 89%</em>

Step-by-step explanation:

<u>Probability</u>

There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.

We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.

The probability that a randomly chosen student plays basketball or baseball is:

$\displastyle p=\frac{24}{27}$

Simplifying:

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The probability is 0.89 or 89%

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Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .