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3 years ago

Please help me due in an hour

Mathematics

1 answer:

Leokris [45]3 years ago

6 0

Answer:

Ok so it would be square root 1

Step-by-step explanation:

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Which numbers are greater than 0.6? 0.39 0.07 0.8 0.69 0.17

Tasya [4]

0.6>0.39

0.6>0.07

0.6<0.8

0.6<0.69

0.6>0.17

0.8 and 0.69 are greater than 0.6

3 0

3 years ago

Read 2 more answers

Write an algebraic equation to represent the situation.

KatRina [158]

3(x+1) = regular cheese burger

6 0

3 years ago

The diameter of 0 gauge copper wire is 8.252 mm. Find the resistance (in ω) of a 2.40 km length of such wire used for power tran

VashaNatasha [74]

d = diameter of the copper wire = 8.252 mm

r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m

A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶

L = length of the copper wire = 2.40 km = 2400 m

ρ = resistivity of copper wire = 1.68 x 10⁻⁸

resistance of copper wire is given as

R = ρL/A

inserting the above values in the formula

R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)

R = 0.753 ohm

8 0

4 years ago

The expression -310 + 15m represents a submarine that began at a depth of 310 feet below sea level and ascended at a rate of 15

Lesechka [4]

Answer:

190 feet below sea level

Step-by-step explanation:

d = -310 + 15m

d = -310 + 15(8)

d = -310 + 120

d = -190

4 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago