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alexandr402 [8]
4 years ago
13

The town of Maxwell increased its annual budget from $1,300,000 to 1,800,000. Find the percent increase in the budget

Mathematics
1 answer:
aliya0001 [1]4 years ago
6 0
Sorry, but I don't under stand what you are talking about.
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Simplify the expression:<br><br> 5x + 8 – 13y – 4x – 18 + 16y
aleksandrvk [35]

\text{Hey there!}

\text{Simply the equation: 5x + 8 - 13y - 4x - 18 + 16y}

\text{First you have to combine the \bf{like-terms}}

\text{5x-4x = 1x}

\text{-13y + 16y = 3y}

\text{8 + (-18) = -10}

\boxed{\boxed{\bf{Answer: 1x + 3y - 10}}}\checkmark

~\frak{LoveYourselfFirst:)}

4 0
4 years ago
D. 9.9<br> Math question please show work
34kurt
The ans is B
hope this helps

5 0
3 years ago
George buys some first class and second class stamps to put on some letters. Each first class stamp costs 67p, and each second c
Dafna1 [17]

Answer:

£191.36

Step-by-step explanation:

Sum the parts of the ratio, 1 + 4 = 5 parts

Divide 320 by 5 to find the value of one part of the ratio.

320 ÷ 5 = 64 ← value of 1 part of the ratio , thus

4 parts = 4 × 64 = 256

Thus he bought 64 first class and 256 second class.

Cost = (64 × £0.67) + (256 × £0.58)

        = £42.88 + 148.48

        = £191.36

3 0
3 years ago
What is the balue of x in the proportion 2 1/4 / x= 1 1/2/3/35?
never [62]

Answer:

5 2/5

Step-by-step explanation:

(2 1/4) / x = (1 1/2) / (3 3/5)

so

x = (2 1/4) * (3 3/5) / (1 1/2)

7 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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