Let a₁ , a₂ , a₃ , a₄ ,... .be a given sequence.
The common ratio of this sequence is the following:
a₂/a₁ = a₃/a₂ = a₄/a₃ = r
Example: 5, 25, 125, 625, ...The common ration is:
25/5 = 125/25 = 625/125 = 5. So r=5 is the common ratio
Answer:
Can you show a picture? Or like tell us the options?
An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides
assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent
ok, solve initial
x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation
-x-y=-1
<u>x-3y=9 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=1
x-2=1
add 2
x=3
x=3
y=-2
(3,-2)
if we test it in other one
2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep
2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep
solution is (3,-2)
Answer:
Rule 3
Step-by-step explanation:
The values correspond to the equation y=3^x
The value of sine theta = negative eight-seventeenths ⇒ 2nd
Step-by-step explanation:
Let us revise the quadrant of an angle its terminal side passes through a given point
- If the given point is (x , y), then the angle lies in the 1st quadrant
- If the given point is (-x , y), then the angle lies in the 2nd quadrant
- If the given point is (-x , -y), then the angle lies in the 3rd quadrant
- If the given point is (x , -y), then the angle lies in the 4th quadrant
∵ The terminal side of angle Ф passes through P (15 , -8)
∵ x = 15 and y = -8
- P is (x , -y), then the angle Ф lies in the 4th quadrant
∵ The terminal side of angle Ф is the hypotenuse of a right
triangle whose horizontal leg is 15 units and vertical leg
is -8 units
- Use Pythagoras Theorem to find the length of the hypotenuse
∴ Hypotenuse =
units
∵ sinФ = 
∵ The side opposite to Ф is -8
∵ The hypotenuse is 17
∴ sinФ = 
The value of sine theta = negative eight-seventeenths
Learn more:
You can learn more about the trigonometry function in brainly.com/question/4924817
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