Answer: 3sqrt6
Step-by-step explanation:
Answer:
j(x) = 5 |x+9|-23
Step-by-step explanation:
f(x) = |x|
translate left 9 units
y = f(x + C) C > 0 moves it left
g(x) = |x+9|
translate down 23 units
y = f(x) + C C < 0 moves it down
h(x)= |x+9|-23
stretch by a factor of 5
y = Cf(x) C > 1 stretches it in the y-direction
j(x) = 5 |x+9|-23
Answer:
162, 163, and 164.
Step-by-step explanation:
Here we will use algebra to find three consecutive integers whose sum is 489. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 489. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 489
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 489
3X + 3 = 489
3X + 3 - 3 = 489 - 3
3X = 486
3X/3 = 486/3
X = 162
Which means that the first number is 162, the second number is 162 + 1 and the third number is 162 + 2. Therefore, three consecutive integers that add up to 489 are 162, 163, and 164.
162 + 163 + 164 = 489
We know our answer is correct because 162 + 163 + 164 equals 489 as displayed above.
Answer:
a is the answer
Step-by-step explanation:
all work is shown and pictured
Answer:
c
Step-by-step explanation:
