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Wewaii [24]
2 years ago
5

¿que opinas de las personas que no bautizan a sus hijos?

Mathematics
1 answer:
ioda2 years ago
6 0

Answer:

En el bautismo moderno de un bebé o un niño, el padrino o los padrinos hacen una profesión de fe para la persona que se bautiza (el ahijado) y asumen la obligación de actuar como apoderados de los padres si los padres no pueden o se niegan a mantener. la formación religiosa del niño

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The value of a three digit number if the tens digit is c, the hundreds digit is three less than the tens and the ones digit is 0
raketka [301]

Answer:690 580 470 360 250 140

Step-by-step explanation:

These digits are all numbers that the hundreds digit is three less than the tens digit, the ones digit is also zero

5 0
3 years ago
Write a paragraph explaining what scattered plots are and how to solve them. Make sure to give details, key terms and an example
Lunna [17]

Answer:

x = 59°

y = 67°

Step-by-step explanation:

x = y - 8

x + y + 54 = 180

(y - 8) + y = 180 - 54

2y - 8 = 126

2y = 134

y = 67°

x = 59°

Step-by-step explanation:

8 0
3 years ago
When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occu
oee [108]

Answer:

a. 135 g

b. 60.6 min

Step-by-step explanation:

a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.

The chemical equation for the reaction is given below

Cu²⁺(aq) + 2e⁻ → Cu(s)

We find the number of moles of Cu that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = ‭14,400‬ s

So, n = It/F = 28.5 A × ‭14,400‬ s/96485 C/mol = ‭410,400‬ C/96485 C/mol = 4.254 mol

Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu

Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol

So, m = n'M

= 2.127 mol × 63.546 g/mol

= 135.15 g

≅ 135 g to 3 significant figures

b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?

The chemical equation for the reaction is given below

Au⁺(aq) + e⁻ → Au(s)

We need to find the number of moles of Au in 37.1 g

So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol

So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol

Since 1 mol of Au is deposited  by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons

We find the time it takes to deposit 0.188 mol of electrons that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time

So, t = nF/It

= 0.188 mol × 96485 C/mol ÷ 5.00 A

= ‭18173.30‬ C/5.00 A

= 3634.66 s

= 3634.66 s × 1min/60 s

= 60.58 min

≅ 60.6 min to 3 significant figures

6 0
3 years ago
What is the answer P=4x+qx-5
Nastasia [14]

p=qx+4x−5 would be the answer to your problem. Math Papa is a good website to use for alegebra or math



8 0
3 years ago
Read 2 more answers
The diameter of this beach ball is 12 inches.
OLEGan [10]
904.78 is the amount of air it can hold.
3 0
3 years ago
Read 2 more answers
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