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HACTEHA [7]
3 years ago
5

How do you find the area of 3/4ft and 5ft

Mathematics
2 answers:
Vesna [10]3 years ago
7 0
To find the area of an object you must multiply the two numbers given. base and height. the base is the bottom horizontal part and height is the vertical side. so multiply 3/4 and 5. you should get your answer
erastova [34]3 years ago
6 0
You add them together to get 5 and 3/4 feet or 5.75 feet.
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Can you help me find length bc please!!!!
masya89 [10]

Remark

You are dealing with a right angle triangle. You can use one of Sin(x) Cos(x) or Tan(x). Since the Hypotenuse is involved and since you are given the adjacent side, Cos(71) is what you will need.

Solution

H = BC

Cos(x) = adjactent / hypotenuse

Cos(71) = 6.3 / H            Multiply both sides by H

H * Cos(71) = 6.3            Divide by Cos(71)

H = 6.3 / cos(71)             Cos(71) = 0.32557

H = 6.3 / 0.32557          Divide

H = BC = 19.351                       Answer

6 0
3 years ago
A colony of bacteria is growing exponentially according to the function below, where t is in hours. About how many hours will it
Ivenika [448]
The function is:
B ( t ) = 4 * e^(0.8 t)
4 * e^(0.8 t) = 400
e^(0.8 t) = 400: 4
e^(0.8 t) = 100   / ln
ln e^(0.8 t) = ln 100  ( and since: ln e = 1 and ln e^x = x * ln e )
0.8 t = 4.6
t = 4.6 : 0.8 = 5.76 ≈ 6
Answer:
D ) 6 hours.
4 0
3 years ago
Simplly the square root of 75z^18
notsponge [240]

Answer:5√(3)z^9

Step-by-step explanation:

Square root of 75z^18

√(75z^18)

√(75) x √(z^18)

√(25x3) x (z^18)^(1/2)

√(25) x √(3) x z^(18x1/2)

5 x √(3) x z^9

5√(3)z^9

8 0
3 years ago
Solve the following equation.-3 = x/5
Umnica [9.8K]
I hope this helps you




x/5= -3



x= -3.5



x= -15
7 0
3 years ago
25 points!!!
professor190 [17]

Answer:

x+y=12

Step-by-step explanation:

First, substitute 3y for the spots with x:

2(3y) + 2y = 24

6y+ 2y = 24

8y= 24

y= 3

Then sub in 3 in the y place:

x= 3(3)

x= 9

Then plug in the x and y values in the equation:

9 + 3 =12

Good Luck!!!

plz mark me Brainliest!

3 0
2 years ago
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