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3 years ago

Can you guys help I’m stuck and I don’t understand use models to find each quotient draw but equal groups 328÷2

Mathematics

1 answer:

ser-zykov [4K]3 years ago

6 0

Answer:

164 is the answer‍♀️

Step-by-step explanation:

........ also if its correct i need the brainliest

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100 Points! What are the classifications of each system?

alexdok [17]

Answer:

Part 1) Is a inconsistent system

Part 2) Is a consistent independent system

Part 3) Is a consistent dependent system

see the attached figure

Step-by-step explanation:

we know that

If a system has at least one solution, it is said to be consistent .

If a consistent system has exactly one solution, it is independent .

If a consistent system has an infinite number of solutions, it is dependent

If a system not have solution, it is said to be inconsistent

Part 1) we have

$x+5y=-2\\x+5y=4$

This system of linear equations has two parallel lines (their slopes are equal) with different y-intercept

The lines don't intersect

The system has no solution

therefore

Is a inconsistent system

Part 2) we have

$y=3x+4\\-2x+y=4$

we know that

If two lines have different slopes, then the lines intersect at one point and the system of equations has one solution

In this problem, the lines have different slopes (m=3 and m=2)

The lines intersect at one point

The system has one solution

therefore

Is a consistent independent system

Part 3) we have

$3x+y=4$ ----> equation A

$-6x-2y=-8$ ----> equation B

Multiply equation A by -2 both sides

$-2(3x+y)=-2(4)$

$-6x-2y=-8$ ----> equation C

Compare equation B and equation C

Are identical lines

The system has infinity solutions

therefore

Is a consistent dependent system

4 0

4 years ago

Find all solutions for a triangle with c=70 c=24 and a=25

Slav-nsk [51]

Answer:

see the attachments for the two solutions

Step-by-step explanation:

When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.

When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.

___

Here, the law of sines can be used to solve the triangle:

A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°

B = 180° -70° -A = 31.81° or 8.19°

b = 24·sin(B)/sin(70°) = 13.46 or 3.64