Answer:
Question 1:
Here total number of students GPA is given = 50
Number of people who have GPA more than 3.69 = 5
Therefore,
Pr(That a student has GPA more than 3.69) = 5/50 = 0.1
Here X ~ NORMAL (3.12, 0.4)
so Pr(X > 3.69) = Pr(X > 3.69 ; 3.12 ; 0.4)
Z = (3.69 - 3.12)/ 0.4 = 1.425
Pr(X > 3.69) = Pr(X > 3.69 ; 3.12 ; 0.4) = 1 - Pr(Z < 1.425) = 1 - 0.9229 = 0.0771
Question 2
Here GPA would be above 95.54th percentile
so as per Z table relative to that percentile is = 1.70
so Z = (X - 3.12)/ 0.4 = 1.70
X = 3.12 + 0.4 * 1.70 = 3.80
so any person with GPA above or equal to 3.80 is eligible for that.
Answer:
B, C, and D
Step-by-step explanation:
Answer:
Option (C)
Step-by-step explanation:
If two functions are f(x) and k(x),
(f o g)(x) = f[g(x)]
From the question given in the picture attached,
We have to find the value of (h o k)(1).
(h o k)(x) = h[k(x)]
= h[k(1)]
= h(3) [Since, k(1) = 3]
= 28 [Since, h(3) = 28]
Therefore, (h o k)(1) = 28 will be the answer.
Option (C) will be the correct option.
Answer:
Piecewise functions (or piece-wise functions) are just what they are named: pieces of different functions (sub-functions) all on one graph. The easiest way to think of them is if you drew more than one function on a graph, and you just erased parts of the functions where they aren’t supposed to be (along the ’s); they are defined differently for different intervals of . So is defined differently for different values of ; we use the to look up what interval it’s in, so we can find out what the is supposed to be. Note that there is an e…
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Step-by-step explanation:
