Identify the 16th term of a geometric sequence where a1 = 4 and a8 = −8,748.

Mathematics

1 answer:

Bas_tet [7]3 years ago

4 0

Step-by-step explanation:

The formula used to determine the terms is

an = a1 × rn - 1

It is given that

a1 = 4

a8 = -8,748

Substituting the values in the formula

-8748 = 4 × r8 - 1

r7 = -8748/4

r7 = -2187

r = -3

So the 16th term is

a16 = 4 × 316-1

a16 = -57395628

Therefore, the 16th term is -57395628.

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The equation D=13/v shows that the density of a particular substance equals a mass of 13 grams divided by the volume of the subs

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Answer:

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Step-by-step explanation:

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