B. 2 Points determine a unique line
This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

where
is a compact way to indicate both solutions
and
, while
are the coefficients of the quadratic equation, i.e. we consider the polynomial
.
So, in your case, we have 
Plug those values into the formula to get

So, the two solutions are


We have the following:

solving for x

The solution of x is equal to 28, therefore 12 is not a solution of the equation
Answer:
x = 48
Step-by-step explanation:
3x + 9 = 153
subtract 9 from both sides -9 -9
3x = 144
divide both sides by 3 3x/3 = 144/3
2x + (x + 9) = 153
2(48) + (48 + 9) = 153
96 + 57 = 153
153 = 153