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Alla [95]
3 years ago
15

What is 1.235 repeating as a fraction

Mathematics
1 answer:
beks73 [17]3 years ago
7 0
1.235 Repeating Decimal = 1235/999 as a Fraction


Step-by-Step Solution

1.235 equals 1234/999
as an improper fraction or 1 and 235/999
as a mixed number.
How do you turn 1.235 repeating into a fraction?
Detailed Answer:
Step 1: To convert 1.235 repeating into a fraction, begin writing this simple equation:
n = 1.235 (equation 1)
Step 2: Notice that there are 3 digitss in the repeating block (235), so multiply both sides by 1 followed by 3 zeros, i.e., by 1000.
1000 × n = 1235.235 (equation 2)
Step 3: Now subtract equation 1 from equation 2 to cancel the repeating block (or repetend) out.
1000 × n = 1235.235
1 × n = 1.235/999 x n = 1234
n = 1234/999 (answer)
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Using the binomial theorem , obtain the expansion of :
andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1  6  15  20  15  6  1

Decreasing powers of 1 from 1^{6} to 1^{0}

Increasing powers of 3x from (3x)^{0} to (3x)^{6}

1+3x)^{6}

= 1.1^{6}(3x)^{0} + 6.1^{5}(3x)^{1} + 15.1^{4}(3x)^{2} + 20.1^{3}(3x)^{3} + 15.1²(3x)^{4} + 6.1^{1}(3x)^{5} + 1.1^{0}(3x)^{6}

= 1 + 18x + 135x² + 540x³ + 1215x^{4} + 1458x^{5} + 729x^{6}

--------------------------------------------------------------------------------------

(1-3x)^{6}

= 1.1^{6}(-3x)^{0} + 6.1^{5}(-3x)^{1} + 15.1^{4}(-3x)^{2} + 20.1^{3}(-3x)^{3} + 15.1²(-3x)^{4} + 6.1^{1}(-3x)^{5} + 1.1^{0}(-3x)^{6}

= 1 - 18x + 135x² - 540x³ + 1215x^{4} - 1458x^{5} + 729x^{6}

----------------------------------------------------------------------------------

Collecting like terms from both expressions

(1+3x)^{6} + (1-3x)^{6}

= 2 + 270x² + 2430x^{4} + 1458x^{6}

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1  5  10  10  5  1

Decreasing powers of 1 from 1^{5} to 1^{0}

Increasing powers of 2x from (2x)^{0} to (2x)^{5}

(1+2x)^{5}

= 1.1^{5}(2x)^{0} + 5.1^{4}(2x)^{1} + 10.1^{3}(2x)^{2} + 10.1^{2}(2x)^{3} + 5.1^{1}(2x)^{4}+ 1.1^{0}(2x)^{5}

= 1 + 10x + 40x² + 80x³ + 80x^{4} + 32x^{5}

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3 years ago
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