You can plug 0 into y for the x intercept and 0 into x for the y intercept.
3/4 also equals 12/16 so 12/16+5/16= 17/16 or 1 1/16
Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,

Thus, the required equation of the line is y=x-8.
2^-2 would become 1/2^2 which becomes 1/4.
Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown .
Step-by-step explanation:
Given as :
The two linear equation are
y =
x - 1 ...........1
y =
x - 6 ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e
x - 6 =
x - 1
Or,
x +
x = 6 - 1
Or,
x = 5
or,
x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y =
x - 1
Or, y =
× 5 - 1
or, y =
- 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is (
,
) = (5 , - 2)
Again , put the value of x in eq 2
So, y =
x - 6
Or, y =
× 5 - 6
Or, y =
- 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is (
,
) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer