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Arte-miy333 [17]
1 year ago
13

Solve your equations below and right the algebraic steps, n/12 = 10

Mathematics
1 answer:
sdas [7]1 year ago
7 0
\frac{n}{12}=10

Multiply both sides of the equation by 12

\frac{n}{12}\times12=10\times12n=\text{ 120}

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In a study commuting patterns of people in a large metropolitan area, respondents were asked to report the time they took to tra
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Answer:

b. a person

Step-by-step explanation:

The conducted study demonstrates the commuting patterns of people. Here, the information is collected from a person about amount of time consumes in travel to their work on a certain day of the week. Thus, here the individual is "a person" because the information is collected from a person about their time travel.

6 0
3 years ago
​For your job you need to track the amount of time you spend on each project and your total time. For Project A, you spend 1 hou
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Answer:

answer is 120 min

Step-by-step explanation:

hope it helps

6 0
3 years ago
Pleaseeee helpppppppppp
o-na [289]

Answer:

25 ft^2

Step-by-step explanation:

In direct variation, if y varies directly with x, then the equation has the form

y = kx,

where k is the constant of proportionality. y is proportional to x.

Let's call the area y and the distance x.

Here, the area varies with the square of the distance, so the equation has the form

y = kx^2

Here, y is proportional to the square of x.

We can find the value of k by using the given information.

y = kx^2

When x = 20 ft, y = 16 ft^2.

16 = k(20^2)

k = 16/400

k = 1/25

The equation of the relation is:

y = (1/25)x^2

Now we use the equation we found to answer the question.

What is y (the area) when x (the distance) is 25 ft?

y = (1/25)x^2

y = (1/25)(25^2)

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Answer: 25 ft^2

5 0
2 years ago
Which percent is equal to the given fraction? <br><br><br> 1/20
Makovka662 [10]
1/20 is equal to what fraction?

1*5 = 5
20*5 = 100

5/100 >>>>>  5%

Answer: 5%
4 0
3 years ago
Read 2 more answers
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
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