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gregori [183]
2 years ago
13

1. An object is accelerated at a rate of 5 m/s²? Find the mass of the object if the force exerted on it is 4 x 10⁵dynes. (Note:

1 N = 1 10⁵ dynes)
Given:
Unknown:
Formula:
Solution:
Final answer:​​
Mathematics
1 answer:
torisob [31]2 years ago
8 0

Step-by-step explanation:

\begin{gathered}\frak \red{Given}\:\begin{cases} \:\quad\sf  Acceleration \:of \ \: a\:body\:,\:a\:=\:\pmb{\frak{5\:m/s^2\:}}\:\\ \:\quad\sf Force \:Exerted\:on\:a\:body\:,\:F\:=\:\pmb{\frak{\:4\times 10^5\: dynes\:}}\:\end{cases}\\\\\end{gathered}

<h2><u>Need To Find : </u></h2>

  • The mass of a body ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀

We're Provided with the , Acceleration (a) , and Force Exerted (F) on a body and , we'll find Mass (m) of the object using the <u>relation</u>

 between <u>Force , Mass & Acceleration </u> and, that is : 

\underline {\pmb{\sf \: F\:=\:m\:\times \:a \:}}

\\ \twoheadrightarrow \sf F \:=\:m\:\times \:a

: \rightarrow \sf 4 \:\times 10^5 \:=\:m\:\times \:5\:

\\  \\  \\ \\\twoheadrightarrow \sf 4 \:=\:m\:\times \:5\:\:\Bigg\lgroup \:1 \:N\:=\:1\:\times 10^5\:dynes\:\Bigg\rgroup\\

\\ \twoheadrightarrow \sf 4 \: \:=\:m\:\times \:5\:\\\\\\

\twoheadrightarrow \sf 5m\:=\:4\:\\

\twoheadrightarrow \sf m \cancel{\dfrac{4}{5}}\\\\

\ \twoheadrightarrow \pmb {\underline {\boxed {\purple {\:\frak{ \:m\:\:=\:0.8\:kg\:}}}}}\:\bigstar \: \\

\begin{gathered}\therefore \:\underline {\sf \: Hence,\:Mass\:of\:a\:body\:is\:\pmb{\sf 0.8\:kg\:}\:.}\:\\\\\end{gathered}

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Neporo4naja [7]

Answer:

  174 ft²

Step-by-step explanation:

Assuming you're interested in the area of the figure, you can compute it as the sum of the areas of the triangle and rectangle.

The unknown side of the triangle can be figured from the overall dimension of the rectangle and the two lengths that are not part of the triangle base:

  6 ft + triangle base + 6 ft = 18 ft

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Then the area of the triangle is ...

  A = 1/2bh = 1/2(6 ft)(4 ft) = 12 ft²

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Of course, the area of the rectangle is the product of its length and width:

  A = LW = (18 ft)(9 ft) = 162 ft²

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The total area of the figure is the sum of these:

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Anettt [7]

Answer:

correct option is 2187

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Step-by-step explanation:

Given

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height of cylinder = 17 inches

we will us value of pi as 3.14

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Thus,  lateral surface area for given cylinder is  1281.12 square inches.

_________________________________

second part of surface area is area of two base (upper and lower) of cylinder.

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since there are 2 base

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Thus, area of base is 904.32 sq. in.

_______________________________________

Total surface area of cylinder = area of two base+ lateral surface area of cylinder = 1281.12 square inches + 904.32 square inches

                  = 2,185.44  square inches.

Thus, total surface area is  2,185.44  square inches.

lateral surface area is  640.56 square inches

but option which is closest to calculated value is  2187.

Thus, correct option is 2187

___________________________________________

Note: this problem can be directly solved using formula

total surface area for cylinder = 2\pi r^2 + 2\pi rl

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