Answer:
see below
Step-by-step explanation:
Since AB + BC = AC, x + 3x = 20 → 4x = 20 → x = 5.
AB = x = 5 and BC = 3x = 3 * 5 = 15.
Hmm
well, um
if -4 is a zero then if we subsitute -4 for x, we should get 0
so
0=(-4)²-(-4)-(2k+2)
0=16+4-2k-2
0=18-2k
2k=18
divide by 2
k=9
k=9
the value k is 9
(x - 2)²(x+1)
(x-2)(x-2)
multiply the two brackets together
(x)(x)=x^2
(x)(-2)=-2x
(-2)(x)=-2x
(-2)(-2)=4
x^2-2x-2x+4
x^2-4x+4
(x^2-4x+4)(x+1)
multiply the brackets together
(x^2)(x)=x^3
(x^2)(1)=x^2
(-4x)(x)=-4x^2
(-4x)(1)=-4x
(4)(1)=4
x^3+x^2-4x^2-4x+4x+4
Answer:
x^3-3x^2+4
Y = -x + 3
y = 3/2x - 2
-x + 3 = 3/2x - 2....multiply everything by 2 to get rid of the fraction
-2x + 6 = 3x - 4
-2x - 3x = -4 - 6
-5x = -10
x = -10/-5
x = 2
y = -x + 3
y = -2 + 3
y = 1
solution is (2,1)
