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Alenkinab [10]
3 years ago
6

The coordinate of the vertices for square CDEF translated 3 units right and 4 units up if the vertices are C(-3,1), D(1,5), E(5,

1), and F(1,-3) are. C’(0,5), D(4,6), E,(8,6) and F(4,-1). Is it true or false
Mathematics
1 answer:
ELEN [110]3 years ago
7 0
The statement is false because not all the corresponding point have been translated correctly from the original.

Here are the correct answers:

C: (-3, 1) to (0,5). CORRECT!
D: (1,5) to (4, 9) INCORRECT IN THE CHOICE
E: (5, 1) to (8, 5) INCORRECT IN THE CHOICE
F: (1, -3) to (4, 1) INCORRECT IN THE CHOICE
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Work out the lengths of sides a and b.
nlexa [21]

Answer:

No solution is possible since you failed to provide the necessary information

Step-by-step explanation:

3 0
2 years ago
Help quick ❗️❗️ Which sequence of transformations will change did your PQRS to figure P’Q’R’S’?
babymother [125]

Answer:

Counterclockwise rotation about the origin by 90° followed by reflection over the Y-axis ⇒ answer (D)

Step-by-step explanation:

* Lets revise the reflection and the rotation of a point

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) rotated about the origin by angle 90° counter clockwise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clockwise

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise or  

anti-clockwise around the origin

- In our problem

# The vertices of the original figure are:

  P(1 , -3) , Q (3 , -2) , R (3 ,-3) , S (2 , -4)

# The vertices of the image are:

  P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

∵ x and y are switched

∴ The figure is rotated about origin by 90°

∵ The signs of the x-coordinates and the y-coordinates

   didn't change

∴ The rotation is followed by reflection, to know about which

   axis we must to find the images after the rotation

∵ P (1 , -3) ⇒ after rotation 90° counter clockwise is (3 , 1)

∵ Q (3 , -2) ⇒ after rotation 90° counter clockwise is (2 , 3)

∵ R (3 , -3) ⇒ after rotation 90° counter clockwise is (3 , 3)

∵ S (2 , -4) ⇒ after rotation 90° counter clockwise is (4 , 2)

* The images are P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

- The sign of x-coordinates of all of them changed

∴ The rotation followed by reflection over the y-axis

* The answer is ⇒ Counterclockwise rotation about the origin

  by 90° followed by reflection over the Y-axis

7 0
3 years ago
The cosine function reaches a value of 0 when x is equal to
ollegr [7]

Answer:

Step-by-step explanation:

The values ​​of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.

4 0
2 years ago
Four different sets of objects contain 4, 5, 6, and 8 objects, respectively. How many unique combinations can be formed by picki
ser-zykov [4K]

You would multiply all of the numbers to get your answer so it would be 4*5*6*8 which would get you 960.

8 0
3 years ago
Read 2 more answers
How many solutions does the system have? \begin{cases} 5y =15x-40 \\\\ y = 3x-8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 5y=15x−40 y=3x−8 ​ C
Ksenya-84 [330]

Answer:

(C) Infinitely many solutions

Step-by-step explanation:

Converting the lines into the from ax+by+c=0

5y=15x-40\\\Rightarrow 15x-5y-40=0

y=3x-8\\\Rightarrow 3x-y-8=0

\dfrac{a_1}{a_2}=\dfrac{15}{3}=5

\dfrac{b_1}{b_2}=\dfrac{-5}{-1}=5

\dfrac{c_1}{c_2}=\dfrac{-40}{-8}=5

So, \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}.

Hence, these lines have infinitely many solutions.

3 0
2 years ago
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