Answer:
![n\geq 23](https://tex.z-dn.net/?f=n%5Cgeq%2023)
Step-by-step explanation:
-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:
![n\geq (\frac{z\sigma}{ME})^2](https://tex.z-dn.net/?f=n%5Cgeq%20%28%5Cfrac%7Bz%5Csigma%7D%7BME%7D%29%5E2)
Where:
is the standard deviation
is the desired margin of error.
We substitute our given values to calculate the sample size:
![n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23](https://tex.z-dn.net/?f=n%5Cgeq%20%28%5Cfrac%7Bz%5Csigma%7D%7BME%7D%29%5E2%5C%5C%5C%5C%5Cgeq%20%28%5Cfrac%7B1.96%5Ctimes%2012%7D%7B5%7D%29%5E2%5C%5C%5C%5C%5Cgeq%2022.13%5Capprox23)
Hence, the smallest desired sample size is 23
Answer:
B on ed 2020
Step-by-step explanation:
an r value of 1 would be a graph that has a linear line going up one then
to the right one so the closest to that is the 2nd graph (B)
Answer:
the first blank is 10
and the second blank is 5
Step-by-step explanation:
Answer:
q = 15
Step-by-step explanation:
Given
f(x) = x² + px + q , then
f(3) = 3² + 3p + q = 6 , that is
9 + 3p + q = 6 ( subtract 9 from both sides )
3p + q = - 3 → (1)
---------------------------------------
f'(x) = 2x + p , then
f'(3) = 2(3) + p = 0, that is
6 + p = 0 ( subtract 6 from both sides )
p = - 6
Substitute p = - 6 into (1)
3(- 6) + q = - 3
- 18 + q = - 3 ( add 18 to both sides )
q = 15
150+3p
p=30
150+3(30)
150+90
240
When p=30 in 150+3p, the final value is 240.