Answer:
The surface area of the pyramid in exact form is 64 +
cm²
The approximated surface area of the pyramid is 174.9 cm²
Step-by-step explanation:
The surface area of the square pyramid is the sum of the area of the base and the area of the four triangular faces
In Δ EFD
∵ m∠EFD = 90°
∵ m∠FDE = 60°
∵ ED = 8 cm
- By using sine ratio to find FE
∵ sin(∠FDE) = 
∴ sin(60) = 
- Multiply both sides by 8
∴ FE = 8 sin(60°)
∴ FE =
cm
In Δ AED
∵ AE = ED
∵ m∠D = 60°
- In any isosceles Δ if measure of an angle is 60, then the
triangle is equilateral Δ
∴ Δ AED is an equilateral Δ
∴ AD = 8 cm
∵ The pyramid has 4 identical triangular faces
∵ Area of each Δ =
× base × height
∵ AD is the base and FE is the height
∴ Area of each Δ =
× 8 × 
∴ Area of each Δ =
cm²
∵ Surface area of the pyramid = Area of base + 4 area of a Δ
∵ Area of base = 8²
∴ Area of base = 64 cm²
∴ Surface area of the pyramid = 64 + 4 × 
∴ Surface area of the pyramid = 64 + 
The surface area of the pyramid in exact form is 64 +
cm²
The approximated surface area of the pyramid is 174.9 cm²
1100/80=13.75,the answer is 13.75.So Tyler earn 13.75
Answer:
a) 64° each
b) 15.78 cm
c) 51.78 cm
Step-by-step explanation:
a) (180 - 52)/2 = 64°
b) cos 64 = x/18, x = 7.89, 2x = 15.78 cm
c) 18 + 18 + 15.78 = 51.78 cm
A vertical asymptote simply means that the function is undefined at a certain point. We are given that it occurs at x=25. Notice that x is in the denominator and if the denominator equals 0, the entire function is undefined. <em>a</em> and <em>k</em> are simply constants, and so they can take on any value. This is one of infinite solutions to this question:

Notice that when you plug in x=25, the denominator is 0 and the function is undefined making it a vertical asymptote.
Hope I could help!
The answer is A.
You can recognize the pattern of an exponential equation to know the answer, but to prove it, the easiest way is to inspect the elements and find exponential.
In this case, y = 2^x power
2^1 = 2
2^3 = 8
2^5 = 32
2&7 = 128
That is the best reason for the answer I can give sadly.