Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
Answer:
int sum = 0;for(int[] m : arr2){ for(int n : m) { sum += n; }}
Explanation:
Option A is wrong because it will throw an ArrayIndexOutOfBoundsException during the last iteration of the first and second loop.
the number of accessible element in the first dimension of arr2 is from 0 to arr2.length-1 but the loop specify 0 to arr2.length which will be the first cause of the error
while that of the second dimension specify 0 to arr2[j].length instead of 0 to arr2[j].length-1
Option B is also wrong because the expression j-- will decrement the value of j instead of incrementing it and the second dimension specify 0 to arr2[j].length instead of 0 to arr2[j].length-1 which will also cause an ArrayIndexOutOfBoundsException.
Option C will successfully calculates the sum of all elements arr2.
Answer:
Because the LAN has a DHCP server configured in it.
Explanation:
DHCP stands for Dynamic Host Configuration Protocol and its a client/server protocol that assigns an IP address and other configuration parameters to automatically connect a computer to the network and start browsing the internet
Answer:
The answer is option d.
Explanation:
The 'querySelectorAll' function enables you to extract the list of items that fit the CSS selector you choose. It's just a way to find JavaScript components. It is very adaptable and enables you to search for tags, classes, IDs, combinations of parent/child, attributes, etc.
In other words, we can say that the querySelectorAll() method returns all the matches. and other options are not correct that can be described as follows:
- In option a and b, the object is a collection of unordered properties, that can be changed in adding, deleting and read-only. The option a is an attribute, that is used in CSS and option b is used in JavaScript for the property name.
- In option c, It reverts the element with the fixed value, that has the ID attribute.