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3 years ago

12

Please help me on this

1 answer:

kkurt [141]3 years ago

6 0

Answer:

answe are ,

1). (n+10)

2) (3n+4)

3). (7x -9)

4). (x+6)

5). (5x+2)

6). (x+10)

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The gas tank of a certain car contains 13 gal when the driver of the car begins a trip. For each mile driven by the driver, the

Stels [109]

Answer:

a. write a linear function for the number of gallons of gas in the tank in terms of the number of miles driven.

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2 years ago

14. If a = 4, b = 2, c = 5 then 4a − (b + c) =

zmey [24]

Answer:

9

Step-by-step explanation:

What you do is you plug in the a number into a, b into b, and c into c.

4(4)-(2+5)=9.

Hope this helps.

6 0

3 years ago

Solve the inequality:<br> 4 +5t < 19

iogann1982 [59]

4 + 5t < 19
Subtract 4 from both sides
5t < 19 - 4 or 5t < 15
Divide both sides by 5
t < 3

4 0

3 years ago

Read 2 more answers

Indicate in standard form the equation of the line passing through the given points, writing the answer in the equation

Kryger [21]

Answer:

$y + x - 6 = 0$

Step-by-step explanation:

Given

$M(0,6) \ and \ N(6,0)$

Required

Find the equation of the line

First, the slope of the line has to be calculated using the following formula;

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$where\ (x_1,y_1) = (0,6) \ and \ (x_2,y_2) = (6,0)$

So, the equation becomes

$m = \frac{0 - 6}{6 - 0}$

$m = \frac{-6}{6}$

$m = -1$

The equation of the line can then be calculated using

$m = \frac{y - y_1}{x - x_1} \ or \ m = \frac{y - y_2}{x - x_2}$

$Using \ m = \frac{y - y_1}{x - x_1}$

$-1 = \frac{y - 6}{x -0}$

$-1 = \frac{y - 6}{x}$

Multiply both sides by x

$-1 * x = \frac{y - 6}{x} * x$

$-x = y - 6$

Add x to both sides

$x -x = y - 6 + x$

$0 = y - 6 + x$

Reorder

$y + x- 6 = 0$

$Using \ m = \frac{y - y_2}{x - x_2}$

$-1 = \frac{y - 0}{x - 6}$

$-1 = \frac{y}{x - 6}$

Multiply both sides by x - 6

$-1 * (x-6) = \frac{y}{x - 6} * (x-6)$

$-1 * (x-6) = y$

$-x+6 = y$

Add x - 6 to both sided

$x - 6 -x+6 = y +x - 6$

$0 = y + x - 6$

$y + x - 6 = 0$

Hence, the equation of the line is $y + x - 6 = 0$

3 0

3 years ago

Complete the set of ordered pairs for the relation.

Nonamiya [84]

The set of ordered pairs are $(-2,18),(-1,20),(0,22),(1,24),(2,26)$

Step-by-step explanation:

Given that the relation $\{(x, y): y=2(x+11) \text { and } x \in(-2,-1,0,1,2)\}$

To find the set of ordered pairs, let us substitute the value for x in the relation $y=2(x+11)$

For $x=-2$ ,

$\begin{aligned}y &=2(-2+11) \\&=2(9) \\y &=18\end{aligned}$

The ordered pair is $(-2,18)$

For $x=-1$ ,

$\begin{aligned}y &=2(-1+11) \\&=2(10) \\y &=20\end{aligned}$

The ordered pair is $(-1,20)$

For $x=0$ ,

$\begin{aligned}y &=2(0+11) \\&=2(11) \\y &=22\end{aligned}$

The ordered pair is $(0,22)$

For $x=1$ ,

$\begin{aligned}y &=2(1+11) \\&=2(12) \\y &=24\end{aligned}$

The ordered pair is $(1,24)$

For $x=2$ ,

$\begin{aligned}y &=2(2+11) \\&=2(13) \\y &=26\end{aligned}$

The ordered pair is $(2,26)$

Thus, the set of ordered pairs is $(-2,18),(-1,20),(0,22),(1,24),(2,26)$

7 0

3 years ago