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Kobotan [32]
3 years ago
6

Can y’all help solve this

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

C) 101

Step-by-step explanation:

∠4 + ∠ 5  = 180   {Co-interior angles are supplementary }

∠4 + 79 = 180

      ∠4= 180 - 79

      ∠4 = 101

alisha [4.7K]3 years ago
6 0
When converted to a household measurement, 9 kilograms is approximately equal to a
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I need help on this.
victus00 [196]

Answer:

.75


Step-by-step explanation:

Not sure

4 0
3 years ago
Read 2 more answers
Ali bought 2.15 pounds ogf turkey at 7.89 per pound and 1.87 poundb lamb at 7.89 per pound Which expression does NOT show the to
eduard

Answer:

Total = $31.71

Step-by-step explanation:

Given data:

pounds of turkey = 2.15 at a rate of 7.89/ pound

pounds of lamb = 1.87 at a rate of 7.89/ pound

cost of each item as

cost(T) = 2.15 × 7.89

cost(T) = $16.96

And for lamb

cost(L) = 1.87 × 7.89

cost (L) = $14.75

Total cost will be the summation of both cost

Total = 16.96 + 14.75

Total = $31.71

6 0
3 years ago
Read 2 more answers
A) Find an equation of the line:
nikklg [1K]

A) y=-2x-2

y/x=slope -4/2=-2 y-intercept=b=-2 (put in y=mx=b form)

B) y=15/4x-1 or y=3.75x-1

C) y=-0.6664x-3(I DONT THINK THIS ONE IS RIGHT CHECK IT FIRST)

6 0
3 years ago
1. Wyznacz miary kątów a, ß, y id.
Ad libitum [116K]

Answer:

Step-by-step explanation:

What the heck do you mean

7 0
3 years ago
Suppose the scores of students on an exam are Normally distributed with a mean of 405 and a standard deviation of 69. Then appro
soldi70 [24.7K]

Answer:

 198 and 612

Step-by-step explanation:

We are given that the scores are normally distributed.

The mean of the data is 405.

The standard deviation of this data is 69.

Empirical rule states that for a normally distributed data that

  • about 68% data lies between \mu \pm 1\sigma that is one standard deviation from mean.
  • about 95% data lies between \mu \pm 2\sigma that is one standard deviation from mean.
  • about 99.7% data lies between \mu \pm 3\sigma that is one standard deviation from mean.

Thus, 99.7% of data will lie between 405 \pm 3(69) that is it will lie in the range (198,612)

7 0
3 years ago
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