Answer:
51-2x
Step-by-step explanation:
Answer:
Compound interest = $365.4
Step-by-step explanation:
Given:
Amount borrowed = $6,000
Rate of interest = 3%
Number of year = year
Find:
Compound interest
Computation:
A = P[1+r]ⁿ
Amount after 2 year = 6,000[1 + 3%]²
Amount after 2 year = 6,000[1 + 0.03]²
Amount after 2 year = 6,000[1.03]²
Amount after 2 year = 6,000[1.0609]
Amount after 2 year = 6,365.4
Compound interest = Amount after 2 year - Amount borrowed
Compound interest = 6,365.4 - 6,000
Compound interest = $365.4
Five and nine hundred twenty-one thousandths
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:
y=9%
Step-by-step explanation:
x=18%
y=9%
It is in a pattern like x=y+y