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Svetradugi [14.3K]
4 years ago
9

How do you work out 8 something 2 something 1 =24 ?

Mathematics
2 answers:
zaharov [31]4 years ago
5 0
8<em>  times (</em>  2<em>  plus</em>  1 )  =  24
Paraphin [41]4 years ago
5 0
8\cdot(2+1)=24
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Find the unit rate for 6 and 2/5 cookies in 4 minutes ​
Wewaii [24]

Answer:

Step-by-step explanation:

6 2/5 cookies in 4 mins

To find the unit rate in minutes, divide 6 2/5 and 4 by 4.

In one minute is 1.6 cookies.

To find the unit rate in cookies, we divide by 6 2/5.

For one cookie, there are 5/8 minutes.

7 0
3 years ago
A box holds 25 pounds of cans. Each can weighs 8 ounces. How many cans does each box hold?
OverLord2011 [107]

1 pound = 16 ounces.

1 can weighs 8 ounces, so 2 cans weigh 8 +8 = 16 ounces, which is 1 pound.

Multiply total pounds by number of cans per pound:

25 pounds x 2 cans per pound = 50 total cans.

6 0
3 years ago
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What are the domain and range of f(x) = 4x – 8?
Liula [17]
The domain is x and the range is f(x)
5 0
3 years ago
Jerry deposited 20,000 on an investment that will give 1,750 for every year that his money stays in the account. How much money
lesya692 [45]

Answer:

$34,000

Step-by-step explanation:

Jerry will get $1,750 for every year that his money stays in the account thus for 8 years he will get:

8*1,750 = $14,000

Together with the deposited money:

$20,000 + $14,000 = $34,000

By the end of year 8 there will be $34,000 of Jerry's account.

3 0
2 years ago
Evaluate each expression.
Virty [35]

Answer:

<em>720</em>

<em>12</em>

<em>120</em>

Step-by-step explanation:

<u>Factorials</u>

We must recall that the factorial of a number n (positive or zero) is the product of all the integers from n down to 1

n!= n(n-1)(n-2)...1

Let's evaluate the given expressions

6!=6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1=720

Similarly

3!\cdot 2!=(3\cdot 2\cdot 1)\cdot (2\cdot 1)=6\cdot 2=12

Finally

\displaystyle \frac{6!}{3!}=\frac{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{3\cdot 2\cdot 1}

\displaystyle \frac{6!}{3!}= \frac{720}{6}=120

3 0
3 years ago
Read 2 more answers
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