Answer:
The first option....x^2-x-12
Step-by-step explanation:
Answer:
Let's define:
A = # of students in group A
B = # of students in group B
C = # of students in group C.
"The total number of students who could attend a field trip is represented by the variable t."
This can be written as:
A + B + C = t.
"The number of students in Group A is less than the number in Group B."
Here we have a strictly "less than", then this is written as:
A < B.
"Group A has 6 students more than 1/4 the total number of students"
A = t/4 + 6
"Group B has 3 less than the total number of students"
B = t - 3.
Then we have the equations:
A + B + C = t.
A = t/4 + 6
B = t - 3.
A < B.
We could replace the second and third equatio in the fourth one, to get:
t/4 + 6 < t - 3.
t/4 + 9 < t
9 < t - t/4
9 < t*(4/4 - 1/4)
9 < t*(3/4)
(4/3)*9 < t
12 < t.
Then we found an inequality that defines the minimum possible value of t,
The given function is:
The statement A is true. Substituting x = 1 in given expression we get 0. So, (1,0) is the x-intercept of the function.
The statement B is false. There is no y-intercept of the function.
The statement C is false. The base of log is less than 1, so it will be a decreasing function.
The statement D is true.
The statement E if true. Range of the log function is set of all Real numbers.
The statement F is true. The given log function is defined for values of x greater than 0.
So the correct options are A, D, E and F
2 steering wheels manufactured each hour were defected
There were 50 steering wheels manufactured per hour
The fraction is
Divide 2, which is the numerator by 50, which is the denominator
2÷50=.04
To change any decimal into a fraction, multiply by 100
The multiply .04 by 100 to change into a percentage
.04×100=4.⇒4%
4% is the percentage of defective steering wheels
Answer:
a)=0.6826
b)=0.6331
c))=0.1662
d)0.0016
Step-by-step explanation:
Binomial Distribution refers to the distribution in whereby only two possible outcomes. It takes place whether the event is happening or not happening , irrespective of the number of trials.
Given:
p = 0.6, q = 1 - p = 0.4
a)P(At least 3 out of 5 days) = P(3) + P(4) + P(5)
P(X≥3)=P(X=3)+P(X=4)+P(X=5)=5C3×0.63×0.45−3+5C4×0.64×0.45−4+5C5×0.65×0.45−5
10×0.63×0.45- 3+5×0.64×0.45 - 4+1×0.65×0.45 - 5
=0.6826
(b)P(At least 6 out of 10 days)
p(X = 6) + p(X = 7) + p(X = 8) + p(X = 9) + p(X = 10) =
0.2508 + 0.2150 + 0.1209 + 0.0403 + 0.0061 = 0.6331
(c)P(5 out of 10 days )
checking the binomial distribution table
p(X < 5) =
p(X = 0) + p(X = 1) + p(X = 2) + p(X = 3) + p(X = 4) =
0.0001 + 0.0016 + 0.0106 + 0.0425 + 0.1114 =0.1663
(d)
P(X<6)=0.0016
P(X<6)=0.0016
from answer from option D, it shows that there is 0.16% chance distribution from the 20 random sample,then it can be concluded that P<0.60