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avanturin [10]
3 years ago
11

Does 2/3 and 10/16 form a proportion? explain

Mathematics
2 answers:
Romashka [77]3 years ago
5 0
No because you would not be able to divide them by a number and get the same answer so no they are not proportional
ycow [4]3 years ago
4 0
No they don't. If they don't match up equally then it isn't proportional. An example for this is

1/2 is and 8/16 make a proportion because 8 is half of 16 and 1 is half of 2.
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The following two-way table describes student's after school activites. Find the probability that a randomly selected student is
stiv31 [10]

The probability that a randomly selected student is in music/drama is 25%

<h3>How to determine the probability?</h3>

From the table, we have the following values

Music/Drama = 7 + 13 + 5 = 25

Total = (20 + 20 + 25 + 7 + 13 + 5 + 3 + 2 + 5) = 100

The probability is then calculated as:
P = Music/Drama / Total

So, we have:

P = 25/100

Express as percentage

P = 25%

Hence, the probability that a randomly selected student is in music/drama is 25%

Read more about probability at:

brainly.com/question/251701

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4 0
2 years ago
1. Two students went to McDonald's. They each bought the same snack, which included a shake
Sindrei [870]

Answer:

12-2=10 b=10

Step-by-step explanation:

6 0
3 years ago
can someone help me?, I had the notes in my notebook but the notebook got full, so I threw it away not thinking I was gonna need
Natalija [7]

Step-by-step explanation:

hope this helps you

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5 0
3 years ago
72% and 89% confirm that the mean theses two are scores is 80.5%
german

Answer:

correct. the mean of 72 and 89 is 80?5

Step-by-step explanation:

find the mean to confirm it.

(a+b)/2

72+89= 161

161/2=80.5

3 0
3 years ago
Please help me find limit​
cluponka [151]

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  \displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}

4 0
3 years ago
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