Work done on cart
:
W
=
6000
J
Kinetic energy of cart
:
E
K
=
6000
J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300
N
⋅
20
m
⇒
W
=
300
kg
⋅
m s
−
2
⋅
20
m
⇒
W
=
300
⋅
20
kg
⋅
m
2
s
−
2
⇒
W
=
6000
kg
⋅
m
2
s
−
2
∴
W
=
6000
J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000
Answer:
1. 20
2. 23
3. 6
Step-by-step explanation:
We have that:
f(x) = 2x
g(x) = x² + 1
f(g(x)) is the composite function of f and g. So
f(g(x)) = f(x²-1) = 2(x²+1) = 2x² + 2
1. f(g(3))
f(g(x)) = 2x² - 2 = 2(3)² + 2 = 18 + 2 = 20
2. f(3)+g(4)
f(3) = 2(3) = 6
g(4) = 4² + 1 = 17
f(3) + g(4) = 6 + 17 = 23
3. f(5) - 2g(1)
f(5) = 2(5) = 10
g(1) = (1)² + 1 = 2
f(5) - 2g(1) = 10 - 2*2 = 10 - 4 = 6
Step-by-step explanation:
Claim: There's 14 Goats and 9 Chickens!!
Data:
Working with the Provided Information.
Let the Number of goats be x
let the Number of Chickens be y
x + y = 23..... (i)
Since the goat Possesses Two Pair of Legs... Which is a Total of 4 Legs... We say Let its Contribution be 4x.
The Chicken has Only a Pair Of Legs...Which is a total of 2 legs.... We say let its contribution be 2y
4x + 2y = 74 .....(ii)
BRINGING BOTH EQUATIONS TOGETHER.
x + y = 23
4x + 2y = 74
From Eqn i
x= 23 - y
Substitute into eqn ii
4(23 - y ) + 2y = 74
92 - 4y + 2y = 74
92 - 2y = 74
2y = 92 - 74
2y = 18
y= 9.
Substitute y into any of the eqns to get x
x + y = 23
x + 9=23
x = 23 - 9
x = 14
This simply proves that there are 14 Goats and 9 Chickens!!!.
HAVE A GREAT DAY!
The building blocks of proteins are amino acids.
2/14 just add the numerators and denomentators
