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g100num [7]
3 years ago
15

The sum of two integers is eight. give two examples of what this number could be

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0
Well is could be 4 plus 4 , or 16- 8
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The two largest lizards in the United States are the Gila monster and the chuckwalla. The average Gila monster is 0.608 meter lo
Zanzabum

Answer:

1.54 to the nearest hundredth

Step-by-step explanation:

Divide the average length of a Gila lizard by length of a chuckwalla.

= 0.608 / 395

4 0
2 years ago
A deli is offering two specials. The roast beef special gives a profit of $2.30 per sandwich, whereas the turkey special gives a
Sedaia [141]
We put the information above in a table as shown below
The number of bread available is 120, so the first constraint is 
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The next constraint is the profit 

7 0
3 years ago
Simplify the expression.<br> -1 + (-3) - (-5) =
Mashcka [7]

Answer:

=-1)+(-3)-(-5)

=-1-3+5

=-4+5

=1

Step-by-step explanation:

answer is to your question is 1.

5 0
2 years ago
Read 2 more answers
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
Help pls the first questions option is<br> 25,40,75<br> And the next option is <br> 40,75,140
Pachacha [2.7K]

Answer:

C is 40 and D is 75

Step-by-step explanation:

look at the angle

5 0
3 years ago
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