No, because let’s say for example that something cost $100.00 so you take 20% (or $20) off of the 100 and you’re left with $80.00. Well then you have your 10% off coupon so you take 10% off of 80, which is 8 dollars. So now you’re at $72.00.
But if we just took off 30% from 100 originally, you would be at $70.00
So no it wouldn’t be the same. If you wanted to check the idea yourself just use different numbers and see if they match at the end.
The answer I got is (2x^2+x-15)
Answer:
(a) t = ±2
(b) t ∈ {0, 1}
(c) In navigation terms: east by north. The slope is about 0.42 at that point.
Step-by-step explanation:
(a) dy/dx = 0 when dy/dt = 0
dy/dt = 3t^2 -12 = 0 = 3(t -2)(t +2)
The slope is zero at t = ±2.
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(b) dy/dx = (dy/dt)/(dx/dt) = <em>undefined</em> when dx/dt = 0
dx/dt = 6t^2 -6t = 6(t)(t -1) = 0
The slope is undefined for t ∈ {0, 1}.
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(c) At t=3, dy/dx = (dy/dt)/(dx/dt) = 3(3-2)(3+2)/(6(3)(3-1)) = 15/36 = 5/12
The general direction of movement is away from the origin along a line with a slope of 5/12, about 22.6° CCW from the +x direction.
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The first attachment shows the derivative and its zeros and asymptotes. It also shows some of the detail of the parametric curve near the origin.
The second attachment shows the parametric curve over the domain for which it is defined, along with the point where t=3.
3: 8 4: 11 6: 15 7: 17 8: 9 10: 7 11: 13 12: 9