a rental car agency charges $210.00 per week plus $0.25 per mile to rent a car. How many miles can you travel in one week for 33
2 answers:
You might be interested in
This is for the first page
Answer: answer to question 17 is r=32/7, answer to question 18 is m=-12, answer to question 19 is k=-9, answer to question 20 is p= No solution, answer to question 21 is x= infinite solutions, answer to question 22 is x= -4.
Step-by-step explanation:
This picture is for the second page
Answer:
2.87%
Step-by-step explanation:
We have the following information:
mean (m) = 200
standard deviation (sd) = 50
sample size = n = 40
the probability that their mean is above 21.5 is determined as follows:
P (x> 21.5) = P [(x - m) / (sd / n ^ (1/2))> (21.5 - 200) / (50/40 ^ (1/2))]
P (x> 21.5) = P (z> -22.57)
this value is very strange, therefore I suggest that it is not 21.5 but 215, therefore it would be:
P (x> 215) = P [(x - m) / (sd / n ^ (1/2))> (215 - 200) / (50/40 ^ (1/2))]
P (x> 215) = P (z> 1.897)
P (x> 215) = 1 - P (z <1.897)
We look for this value in the attached table of z and we have to:
P (x> 215) = 1 - 0.9713 (attached table)
P (x> 215) =.0287
Therefore the probability is approximately 2.87%
