Question

A car dealer just took delivery on forty new cars. He plans to put four of these cars on display at the front of the lot. In how many ways can the dealer combine four of the forty cars if order is not important?
A. 1,096,680
B. 91,390
C. 45,695
D. 2,193,360

Answer 1

Answer:

B. 91,390

Step-by-step explanation:

I've had this question before, I don't like'em, but that's the answer.

Answer 2

Answer:

option B

Step-by-step explanation:

$40C_4 = \frac{40\times 39 \times 38 \times 37}{1 \times 2 \times 3 \times 4} = 91,390$