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2 years ago

7

Y=-x^2+8 y= =3/4x– 3

1 answer:

Dmitrij [34]2 years ago

8 0

Answer:

Yy8cgucucy8cc8yc8ygf7yy7 gdyrvdysrtu ui

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Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.

SSSSS [86.1K]

Answer:

$\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}$

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

$-x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}$

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C your welcome have a nice day

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