Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm
Width=scale÷Actual = 1/50 = 1×50 = 50cm
Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2
Area of the electronic board is 9000 cm2
Answer: 7.5
Form your proportion. Let x be the width of QRST.
Length of ABCD Length of QRST
----------------------- = -------------------------
Width of ABCD Width of QRST
8/5 = 12/x
Solve for x by cross-multiplying.
(8)(x) = (12)(5)
8x = 60
x = 7.5
█ Question <span>█
</span><span>One day at White Cliffs, the maximum daytime temperature was 46°C.
The overnight minimum was 57°C colder than the maximum had been.
What was White Cliffs’ overnight minimum temperature?
</span>█ Answer <span>█
</span>
Please look at the below screenshot.
<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>
Answer:
7
Step-by-step explanation:
PEMDAS
3-2=1
x
7
=
7
