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3 years ago

Someone help with #1

Mathematics

2 answers:

Drupady [299]3 years ago

6 0

My answer was wrong, please delete this

snow_lady [41]3 years ago

4 0

Ok, first we set up 2 equations with the given info
let chips = c & pretzels = p

$5c + 9p = 16.95$
$10c + 10p = 22.50$

next we solve for a single variable in one of the equations (I chose the first one)
$c = \frac{16.95 - 9p}{5}$

now plug it into our second equation
$33.90 - 18p + 10p = 22.50$
simplify
$11.40 = 8p$
divide
$1.425 = p$

next plug p back into our first equation
$5c + 9(1.425) = 16.95$
$5c = 4.125$
$c = .825$

Chips cost = $0.825
Pretzels cost = $1.425

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kondor19780726 [428]

Let us say distance between Eugenia's home and school is x miles.

Speed of Eugenia when she walked from home to school = 3 mph

Speed of Eugenia when she walked from school to home = 7 mph

Total time taken = 45 minutes or 0.75 hours

We know that the speed distance formula is given by:

$speed=\frac{distance}{time}$

$time=\frac{distance}{speed}$

Time taken by Eugenia when she walked from home to school = x/3 hours

Time taken by Eugenia when she walked from school to home = x/7 hours

Total time taken = x/3+x/7

So forming an equation we have,

$\frac{x}{3}+\frac{x}{7}=0.75$

Taking lcd of 7 and 3 as 21,

$\frac{7x}{21}+\frac{3x}{21}=0.75$

$\frac{10x}{21}=0.75$

10x=15.75

Dividing both sides by 10 , we have

x= 1.575

Answer: So we can say that the distance between Eugenia's house and school is 1.575 miles.

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3 years ago

The graph of line p represents y =1/5 x-1 . If the slope of line p is multiplied by -10 to

Katarina [22]

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2 years ago

Solve the rational function of (check image) and check for extraneous solutions

Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

$\frac{5}{x}=\frac{4x+1}{x^2}$

Solving the rational function

$\frac{5}{x}=\frac{4x+1}{x^2}$

Apply fraction across multiply: if $\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5x^2=x\left(4x+1\right)$

Subtract x(4x+1) from both sides

$5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)$

Simplify

$5x^2-x\left(4x+1\right)=0$

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x=0\quad \mathrm{or}\quad \:x-1=0$

Thus, the solution to the equation is:

$x=0,\:x=1$

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In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

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Dima020 [189]

Answer:

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Step-by-step explanation:

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3 years ago