The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
C, x ≥ 14.96
Step-by-step explanation:
Step 1: Add 3.408 to both sides.
2.2x − 3.408 (+ 3.408) ≥ 29.504 (+ 3.408)
2.2x ≥ 32.912
Step 2: Divide both sides by 2.2.
2.2x (÷ 2.2) ≥ 32.912 (÷ 2.2)
x = 14.96
Answer:
12.56 square cm
Step-by-step explanation:
Let A be the area of the sector of circle.
Answer:
The answer to the equation is: 4.648
Acute angle < 90°
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