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earnstyle [38]
2 years ago
11

Over the summer, Stan worked for his uncle at his shop. His summer earnings totaled $8,160. With Stan going back to school in th

e fall, he will be unable to work at his uncle's shop. Stan would like to be able to make money while he's in school, but how? One way that Stan can make his money grow is to invest his cummer income into a bank account paying simple interest at a rate of 6% per year. If Stan keeps his money in there for one year, determine the following: What is the P? What is the r? What is the t?
Mathematics
1 answer:
Ainat [17]2 years ago
5 0

Answer:

2

Step-by-step explanation:

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A news station would like to conduct an exit poll to determine the likelihood that a highly debated amendment will receive enoug
vladimir1956 [14]

Answer:

The expression is n = (\frac{1.645*0.5}{0.03})^2

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

What expression would give the smallest sample size that will result in a margin of error of no more than 3 percentage points?

We have to find n for which M = 0.03.

We have no prior estimate for the proportion, so we use \pi = 0.5. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.645*0.5

\sqrt{n} = \frac{1.645*0.5}{0.03}

(\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2

n = (\frac{1.645*0.5}{0.03})^2

The expression is n = (\frac{1.645*0.5}{0.03})^2

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2 years ago
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