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FinnZ [79.3K]
3 years ago
13

Select the correct answer. Amelia lost her credit card one day while on vacation. She reported the loss to the credit card compa

ny the next day. However, someone had used her card to make purchases worth $1,600 at different shopping outlets. What is the maximum amount that Amelia may have to pay back for the fraudulent charges of $1,600 made on her card? A. $0 B. $50 C. $800 D. $1,600
Mathematics
2 answers:
siniylev [52]3 years ago
3 0

Answer:a

Step-by-step explanation:

densk [106]3 years ago
3 0

Answer:

A) 0

Step-by-step explanation:

she should be able to prove it wasnt her and therefore her credit card company would have to cover it.

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2/3b+5=20−b Solve for b. Both sides have to be equal.
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Answer:

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Step-by-step explanation:

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Hope this helps

3 0
3 years ago
Read 2 more answers
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

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Step-by-step explanation:

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