If 5 consecutive integers is 205,
then a + b + c + d + e = 205
but also, each integer is separated by a difference of 1
⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒ 5a + 10 = 205
⇒ 5a = 195
⇒ a = 39
∴ third term = 39 + 2
= 41
The blank spaces about the passage can be filled with the following correct vocabulary respectively.
- inequality
- strict inequality
- compound inequality
- solution sets
- true
<h3>Inequality</h3>
An <u>inequality</u> is a relation between two numbers and/or expressions that are related via <, >, ≥ or ≤ sign.
A <u>strict inequality</u> is an expression that uses < and >. It tells us that one side is only more or less than the other side.
When 2 simple inequalities are joined by or and, we get a <u>compound inequality</u>.
When solving an inequality, the solution will be a range of values called its <u>solution sets</u>. The inequality will remain <u>true</u> for every single value in this range.
The inequality signs are;
- Greater than >
- Less than <
- Greater than or equal to ≥
- Less than or equal to ≤
- Equal to =
Learn more about inequality:
brainly.com/question/25275758
#SPJ1
Answer:
Ignacio can make 5 clockwise rotations.
Step-by-step explanation:
Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:
4.8r + 49.3 < 74.5 where 'r' is equal to the number of rotations
The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch. Now, solve for 'r':
Subtract 49.3 from both sides: 4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2
Divide 4.8 from both sides: 4.8r/4.8 < 25.2/4.8 or r < 5.25
Since the number of rotations must be less than 5.25, he can make 5 complete rotations.
Answer:
The line AB, with A(Ax, Ay), B(Bx, By) and midpoint M(Mx, My) satisfying:
Ax + Bx = 2Mx
Ay + By = 2My
=>
2 + Bx = 2*1
5 + By = 2*2
=> Bx = 0
=> By = -1
=> B(0, -1)
Hope this helps!
:)
So hmmm notice the picture below
"x" being how many seconds the object was going
and when y = 0, the object hits the ground, either on the moon or on earth
so, if we set y = 0 on each equation, we'll know when that happen, how long of a "x-value" or seconds it took
