For this, we need to know the length of the base at the time of interest. It will be
... A = (1/2)bh
... b = (2A)/h = 2(81 cm²)/(10.5 cm) = 108/7 cm
Differentiate the formula for area and plug in the given numbers.
... A = (1/2)bh
... A' = (1/2)(b'h +bh')
... 3.5 cm²/min = (1/2)(b'·(10.5 cm) + (108/7 cm)·(2.5 cm/min))
... 7 cm²/min = 10.5b' cm + 38 4/7 cm²/min . . . . simplify a bit
... -31 3/7 cm²/min = 10.5b' cm . . . . . . . . . . . . . . . subtract 38 4/7 cm²/min
... (-220/7 cm²/min)/(10.5 cm) = b' ≈ -3.0068 cm/min
The base is changing at about -3 cm/min.
<h3><u>The correct answer is A and B.</u></h3>
Both A and B represent functions, as the same x value is not used twice.
However, with option C, the x value -2 is used twice, and thus it is not a function.
Kekskekeke
Step-by-step explanation:njbnmmk
Answer:
Step-by-step explanation:
Given : Expression
To find : What is the value of the expression ?
Solution :
Step 1 - Write the expression as
Step 2 - Factor 63 and 56 as multiple of 7,
Step 3 - Split the powers
Step 4 - Add the same base power,
Therefore,
Answer: twp is a isosceles because t-w and t-p are the same length
Step-by-step explanation: