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2 years ago

9

Kuissssshi how are you?

20" id="TexFormula1" title=" \sf {3}^{2} \div 9 = " alt=" \sf {3}^{2} \div 9 = " align="absmiddle" class="latex-formula">

pakai cara

2 answers:

Ksju [112]2 years ago

5 0

1
Mark brainliest please
Hope this helps

Shahs

patriot [66]2 years ago

4 0

Answer:

<h2>ᎪꪀsωꫀᏒ</h2>

3²/9

9/9

1

Step-by-step explanation:

hope it's helpful to you

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Solve for x <br> 10x - 72<br> 3x - 4

ratelena [41]

Answer:

16

Step-by-step explanation:

3x - 4 = $\frac{1}{2}$ (10x - 72)

⇔ 6x - 8 = 10x - 72

⇔ 4x = 64

⇔ x = 16

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3 years ago

Find the value or measure. Assume all lines that appear to be tangent are tangent. X=

aev [14]

According to the secant-tangent theorem, we have the following expression:

$(x+3)^2=10.8(19.2+10.8)$

Now, we solve for <em>x</em>.

$\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}$

Then, we use the quadratic formula:

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where a = 1, b = 6, and c = -315.

$\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}$ <h2>Hence, the answer is 15 because lengths can't be negative.</h2>

7 0

1 year ago

Work out the sum of 1 4 , 4 8 and 2 3 . Give your answer as a mixed number in its simplest form

belka [17]

Answer:

1 2/3

Step-by-step explanation:

Given :

Find the sum of 1/2, 4 /8 and 2 /3

1/2 + 4/8 + 2/3

L.c.m = 24

(12 + 12 + 16) / 24

40 / 24

= 1 16/24

= 1 2/3

6 0

3 years ago

Give two integers greater than -8 but less than -4

Lelechka [254]

Answer:

-7 and -6 #markasbrainliest

8 0

3 years ago

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10 points for this

kow [346]

<span>The range would be all real numbers such that 0 ≤ y ≤ 40.

hope this helps!</span>

3 0

3 years ago

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