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larisa [96]
3 years ago
14

Solve for c: c= 5 5/6 x 2 A. 10 5/6 B. 11 2/3 C. 10 2/3 D. 11 5/6

Mathematics
1 answer:
exis [7]3 years ago
6 0

Answer:

B. 11 2/3

Step-by-step explanation:

c = 5 5/6*2

Change the mixed number to an improper fraction

5 5/6 = (6*5+5)/6 = (30+5)/6 = 35/6

c = 35/6 *2

c = 35/6 *2/1

  = 70/6

Now we change it back to a mixed number

6 goes into 70 11 times

11*6 = 66 with 4 left over

11 4/6

We can simplify 4/6 by dividing the top and bottom by 2

11 2/3

You might be interested in
Consider this quadratic equation. 2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?
Mariulka [41]

Answer:

\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}

Step-by-step explanation:

Quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}

x = \frac{3+-7}{4}

Hope this helps and God bless!

6 0
2 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
Add, use decimal models. show the work for 2.1 + 0.59
Ugo [173]
<h2>  2.10</h2><h2>+0.59</h2>

₋₋₋₋₋₋₋₋₋₋₋₋

<h2><em>2.69</em></h2>
6 0
3 years ago
Determine if the pair of triangles are similar or not.
dedylja [7]

Answer: SAS

Step-by-step explanation:

5 0
3 years ago
Last year direct marketing had $122,222 in sales. This year direct marketing's sales are down by 9%. What are direct marketings
Mashutka [201]

Answer:

$111222.02

Step-by-step explanation:

This year = Last year * (100%-9%)

This year = 122222 * 91% = 111222.02

7 0
2 years ago
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