It would be $45. The equation is 500×0. 06×1.5
Answer:
The equations 3·x - 6·y = 9 and x - 2·y = 3 are the same
The possible solution are the points (infinite) on the line of the graph representing the equation 3·x - 6·y = 9 or x - 2·y = 3 which is the same line
Step-by-step explanation:
The given linear equations are;
3·x - 6·y = 9...(1)
x - 2·y = 3...(2)
The solution of a system of two linear equations with two unknowns can be found graphically by plotting the two equations and finding the coordinates of the point of intersection of the line graphs
Making 'y' the subject of both equations gives;
For equation (1);
3·x - 6·y = 9
3·x - 9 = 6·y
y = x/2 - 3/2
For equation (2);
x - 2·y = 3
x - 3 = 2·y
y = x/2 - 3/2
We observe that the two equations are the same and will have an infinite number of solutions
Answer:
the rule is (-1x,+1y) hope this helped
Answer:
So the top right answer choice (x - 10)² = 80 has the same solution as x² - 20x + 20 = 0
Step-by-step explanation:
Let's solve your equation step-by-step.
x² − 20x + 20 = 0
For this equation: a = 1, b = -20, c = 20
1x² + −20x + 20 = 0
Step 1: Use quadratic formula with a = 1, b = -20, c = 20.
x = −b ± √b² − 4ac / 2a
x = −(−20) ± √(−20)² − 4(1)(20) / 2(1)
x = 20 ± √320 / 2
x = 10 + 4√5 or x = 10 − 4√5
Let's try the top right answer choice
(x−10)² = 80
Step 1: Simplify both sides of the equation.
x² − 20x + 100 = 80
Step 2: Subtract 80 from both sides.
x² − 20x + 100 − 80 = 80 − 80
x² − 20x + 20 = 0
For this equation: a = 1, b = -20, c = 20
1x² + −20x + 20 = 0
Step 3: Use quadratic formula with a = 1, b = -20, c = 20.
x = −b ± √b² − 4ac / 2a
x = −(−20) ± √(−20)² − 4(1)(20) / 2(1)
x = 20 ± √320 / 2
x = 10 + 4√5 or x = 10 − 4√5
Let, the number of students = x
Number of teachers = y = 6
Equation would be: 6x + 8.5y = 250
6x + 8.5(6) = 250
6x + 51 = 250
6x = 250 - 51
x = 199 / 6
x = 33.16
Students can't be in fraction, so after rounding-off, it will be 33
In short, Your Answer would be 33 Students
Hope this helps!
