First we will find out the values of a
a/4=b/7
a=4b/7
Now
(a-b)/b
{4b/7-b}/b
(4b-7b)/7b
-3b/7b
-3/7
Answer:
Linear and non-homogeneous.
Step-by-step explanation:
We are given that

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).
We have also find type of differential equation.



It is linear differential equation because this equation is of the form
y'+P(x)y=g(x)
Compare it with first order first degree linear differential equation



Homogeneous equation

Degree of f and g are same.

Degree of f and g are not same .
Therefore, it is non- homogeneous .
Linear and non-homogeneous.
Answer:
a) 0.900
b) 0.400
Step-by-step explanation:
Let I = households getting internet
T = households getting television
Then I = 60%
and T = 80%
(Households that get both services)
a) Households getting at least one service, 
b) Those getting internet only = 
Those getting television only = 
Probability of getting exactly one service = 0.1 + 0.3 = 0.400
Answer: A
Step-by-step explanation:
A
I think, i looked it up, im sorry if im wrong. I tried.
Answer: a, 7ft
Step-by-step explanation: