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3 years ago

Write 37/9 as a mixed number

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

5 0

Answer:

4 1/9 (i believe)

Step-by-step explanation:

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What is the factored equation for f(x)=x+x-6

tekilochka [14]

Answer:

f(x)=2(x-3) yup that's the answer

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3 years ago

Which property or postulate is shown? If A=B and B=C, then A=C.

podryga [215]

This is the transitive property :)

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3 years ago

Read 2 more answers

What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?

Hitman42 [59]

Answer:

Step-by-step explanation:

Given

$y=x^2$

comparing it with standard equation $x^2=4ay$

so 4a=1

$a=\frac{1}{4}$

so Focus of parabola is (0,0)

directrix

y=-a

here $a=\frac{1}{4}$

$y=-\frac{1}{4}$

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4 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

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3 years ago

I need help will mark brainliest

romanna [79]

Answer:

A. -8

B. -8

C. 20

Step-by-step explanation:

5 0

3 years ago