Answer:
a 5
b 9
c 3
d 4
Explanation:
if you were to substitute in these numbers it would be valid.
10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
Yes their is, some people can be hands on learning, or they may use the style of someone telling them how to do it. Theirs also reading to learn. Some other styles as well.
Speed= distance divided by time so s=d/t
first find the individual speeds during each running segment. we get
s=4.0/32=1/8 km per min
s=2.0/22=1/11 km per minute
s=1.0/16=1/16 km per minute
now we take the average. the person jogged a TOTAL of 7.0 km in a TOTAL 70 minutes. so on average, they jogged 7.0/70=1/10 km per minute
