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Agata [3.3K]
3 years ago
8

SOOO I NEED SOME HLP HERE PLSSSS

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

A

Step-by-step explanation:

you just have to mirror it to the other side. so K lands on (4, 1)

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One of the formulas for calculating the correct dosage for a child is as follows: C= a/((a+12)) ∙ 180 C = child’s dosage in mill
bogdanovich [222]
So you already have the formula for calculating the dosage for child with: C = a/(a+12)x 180 ml Not sure why you have double brackets

variables are: a = child's age, so everywhere you have an "a" replace it with the age of child.

Example: 5 year old child

C = 5/(5+12)*180= 5/(17)*180 = 5/3060 = .0016 ml or milligrams
8 0
3 years ago
Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)
Elis [28]

Answer:

Distance between point (3,4) and midpoint of line joining (8,10) and (4,6) = 5 units.

Step-by-step explanation:

Given:

Points:

A(3,4)\\B(8,10)\\C(4,6)

To find distance from point A to midpoint of  BC.

Midpoint M of BC:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\

M=(\frac{8+4}{2},\frac{10+6}{2})\\     [Plugging in points B(8,10)\ and\ C(4,6)]

M=(\frac{12}{2},\frac{16}{2})\\

M=(6,8)\\

Distance between A and M:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

D=\sqrt{(6-3)^2+(8-4)^2} \\   [Plugging in points A(3,4)\ and\ M(6,8)]

D=\sqrt{(3)^2+(4)^2} \\

D=\sqrt{9+16} \\

D=\sqrt{25} \\

D=\pm5

Since distance is always positive ∴ D= 5 units

4 0
3 years ago
What is the difference between the ordered pairs
Irina18 [472]
Order pair are the two point on xy directio and  sheaded are means area below the line
6 0
3 years ago
Read 2 more answers
Find the sum of the convergent series. sigma_n = 1^infinity 12/n(n + 2)
Sindrei [870]

Looks like the series is

\displaystyle\sum_{n=1}^\infty \frac{12}{n(n+2)}

Split up the summand into partial fractions:

\dfrac{12}{n(n+2)}=\dfrac6n-\dfrac6{n+2}

The series has <em>k</em>th partial sum

S_k=\displaystyle\sum_{n=1}^k\frac{12}{n(n+2)}

S_k=\left(6-2\right)+\left(3-\dfrac32\right)+\left(2-\dfrac65\right)+\left(\dfrac32-1\right)+\cdots+\left(\dfrac6{k-2}-\dfrac6k\right)+\left(\left(\dfrac6{k-1}-\dfrac6{k+1}\right)+\left(\dfrac6k-\dfrac6{k+2}\right)

Several intermediate terms cancel to leave us with

S_k=6+3-\dfrac6{k+1}-\dfrac6{k+2}

As k\to\infty, the last two terms converge to 0, so that

\displaystyle\lim_{k\to\infty}S_k=\sum_{n=1}^\infty\frac{12}{n(n+2)}=\boxed{9}

6 0
3 years ago
HELP ME PLEASE!!!<br> The question is in the attachment!
galben [10]
1 meter = 100 cm

To convert meters to cm multiply the given meters ( 0.03) by 100.

0.03 x 100 = 3

The answer would be 3
4 0
3 years ago
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