N(t)= 15000 e^(.07 t)
let's assume 2005 is 0 and 2013 will be 8 years.
n(8)=15000e^(.07*8) = 26260 growth of foxes.
Answer:
-1/10
Step-by-step explanation:
Given that:
5π/3
=5/3×180
=240°
This is in the Quadrant III
The value of cot 5π/3 will be given by:
cost θ=1/tan θ
thus
tan θ
=tan 5π/3
=tan 240
=tan (240-180)
=tan 60
using an equilateral triangle with lengths 2 units
then
tan 60=√3/1
tan 60=√3
hence
tan 240=√3
22=1/2*4(6+b)
22=2(6+b)
22=12+2b
10=2b
Divide both sides by 2:
b=5
The answer is b.
Hope this helps :)