There are 15 pieces of the same size candy in a bag. Four are banana flavored, three strawberry flavored, six cherry flavored, a nd two orange flavored. What would be the probability of picking an orange or a cherry flavored candy from the bag? Round to the nearest tenth.
1 answer:
Answer:
0.5
Step-by-step explanation:
There are 15 pieces of the same size candy in the bag. Two are orange flavored, six cherry flavored. So the probability of picking an orange or a cherry flavored candy is 6/15+2/15=8/15≈0.5
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Answer:
Solutions given:
Velocity ratio V . R =5
effort =500N
efficiency =80%
magnitude of load=?
mechanical advantage [M.A ]
we have
efficiency =M.A/V.R*100%
80=M.A./5*100
80/100*5=M.A
M.A.=4
again
we have
M.A =load/effort
4=load/500
load=500*4
load=2000N
<h3>
<u>the magnitude of the load is 2000N</u> .</h3>
Answer: will it be 4/13?
Step-by-step explanation:
3/100
44 - 12 = 32.
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