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koban [17]
3 years ago
11

If P = (3, 1) and Q = (-3, -7), find The distance PO​

Mathematics
1 answer:
Monica [59]3 years ago
7 0

Answer:

10 units

Step-by-step explanation:

Given data

P = (3, 1) and Q = (-3, -7)

x1=3

y1=1

x2= -3

y2= -7

The expression for the distance between two coordinate is

d=√((x_2-x_1)²+(y_2-y_1)²)

Substitute

d=√((-3-3)²+(-7-1)²)

d=√((-6)²+(-8)²)

d=√36+64

d=√100

d=10 units

Hence the distance is 10 units

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3 years ago
PLEASE HELP ASAP 25 POINTS
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<u>Step-by-step explanation:</u>

 2x - 3y =  -7   →   2(2x - 3y = -7)   →   4x - 6y = -14

-4x + 6y = -10  →   1(-4x + 6y = -10) → <u>-4x + 6y</u> = <u>-10 </u>

                                                                    0  = -24

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Since this makes a false statement, there are no solutions


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