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3 years ago

If P = (3, 1) and Q = (-3, -7), find The distance PO

Mathematics

1 answer:

Monica [59]3 years ago

7 0

Answer:

10 units

Step-by-step explanation:

Given data

P = (3, 1) and Q = (-3, -7)

x1=3

y1=1

x2= -3

y2= -7

The expression for the distance between two coordinate is

d=√((x_2-x_1)²+(y_2-y_1)²)

Substitute

d=√((-3-3)²+(-7-1)²)

d=√((-6)²+(-8)²)

d=√36+64

d=√100

d=10 units

Hence the distance is 10 units

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Perhaps you're concerned with the sequence ...

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1. This is neither arithmetic nor geometric. Ratios of terms are -4/3, -5/3, -6/3.

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{6, 24, 120, 720, ...}

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$\boxed{a_n=\dfrac{(-1)^{n-1}(n+2)!}{3^n}}$

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2 years ago

If P = (3, 1) and Q = (-3, -7), find The distance PO​

If P = (3, 1) and Q = (-3, -7), find The distance PO