The correct expression is A.
(m^3)^-1 (x^2)^5 = (m^-3) (x^10) = x^10 / m^3
√(y2-y1)²+(x2-x1))
Simple Pythagorean Theorem.....
√(12)²+(5²))
√(169)
B.) 13
Taking point <em>Z </em> as the origin, the coordinates of the points on ΔBAD are
given by changing the sign of the coordinates of points in ΔDCB.
- The angle that is congruent to ∠DBA is; <u>D. ∠BDC</u>
Reasons:
The given parameters are;
Triangle ΔBAD is the image of ΔDCB following a rotation of 180°.
Required:
The angle congruent to ∠DBA.
Solution:
Given that the rotation of triangle DCB is 180°, we have that the
coordinates of a point (x, y) in ΔDCB is (-x, -y) in ΔDBA.
Therefore, side DC is parallel to side AB
Which gives;
∠DBA is congruent to ∠BDC by alternate interior angles theorem.
∠DBA ≅ ∠BDC
The angle that is congruent to ∠DBA is; option <u>D. ∠BDC</u>
<u />
Learn more about rotation transformation here:
brainly.com/question/4738741
One half of the sum of a number and 10
n - a number
