Three of the four towns are on the vertices of the triangle ΔCBD, through
which the bearing can calculated.
<h3>Response:</h3>
- The bearing of D from B is approximately <u>209.05°</u>
<h3>Method by which the bearing is found;</h3>
From the given information, we have;
AC = AB = 25 km
∠BAC = 90° (definition of angle between north and east)
ΔABC = An isosceles right triangle (definition)
∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)
The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the
direction of <em>D.</em>
<em />
Therefore;
- The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>
Learn more about bearings in mathematics here:
brainly.com/question/10710413
Answer:
Given
if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form
We need to find the ratio p:q:r
Given p:q = 2/3 : 3 = 2/3 / 3 = 2/9
and p : r = 3/4 : 1/2 = 3/4 / 1/2 = 3/2
Now p/q = 2/9 and p/r = 3/2
We need to make p equal numerators so we get
p/q = 2/9 x 3/3 = 6/27 and
p/r = 2/3 x 3/2 = 6/4
Therefore p : q : r = 6 : 27 : 4
There would be 8 whole(s) in total.
Answer:
Answer A
Step-by-step explanation:
Approach 1
B, C, and D are wrong because angles 1 and 2 are congruent.
Therefore your answer of both being 60°
Approach 2
Let x = angle 1.
360/x = 6
x = 60°.
Therefore Angle 1 is 60°
An interior angle of a hexagon is 120°
Let y = angle 2.
y is half of 120°
So 120/y = 2
y = 60°
