A winning candidate for a national office received 1.2% more votes than his opponent. If there were 52,450,000 votes cast, by
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Answer:
Step-by-step explanation:
Rcode:
library(MASS)
data(DDT,package="MASS")
head(DDT)
colnames(DDT)
print(DDT)
boxplot(DDT)
hist(DDT,main="Histogram for DDT")
fivenum(DDT)
dim(DDT)
outlier_values <- boxplot.stats(DDT)$out # outlier values.
boxplot(DDT, main="DDT", boxwex=0.1)
mtext(paste("Outliers: ", paste(outlier_values, collapse=", ")), cex=0.6)
mean(DDT)
sd(DDT)
Output: * see attachment below*
From Histogram the mean is at the peak
it lies in between 3and 3.5
Form Boxplot we found one outlier and it is 4.64
Fivenum summary is
2.790 3.075 3.220 3.360 4.640
min=2.790
Q1=3.075
Q2=3.220
Q3=3.360
max=4.640
From boxplot the center line is median which cuts the box into 2 equal halves
Distribution is symmetrical
Follows normal distribution.
Mean=3.328
Standard deviation=0.4371531
